what is the work done in moving a test charge q through a distance of 1cm along the equatorial axis of an electric dipole
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Answer:
At every point on equatorial axis, the potential is zero, so work done W = qΔV = 0(zero).
Explanation:
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Answered by
0
Answer:
Work done is given by,
W = qV
Since, the equitorial plane is also equipotential, we have,
Veq=0
Therefore, work done in moving a positive test charge q through a distance of 1 cm is,
W=0
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