Question

Find the area of the square formed by 0,-1), (2, 1) (0, 3) and (-2, 1) taken inorder are
vertices.​

Answer 1

Answer:

8 square units

Step-by-step explanation:

distance between the points ( 0,-1 ) and ( 2,1 )

=

$\sqrt{ {(2 - 0)}^{2} + {(1 + 1)}^{2} } = \sqrt{4 + 4 } = \sqrt{8}$

As all sides of a square are are equal

the distance between remaining points is also root 8...

area of square = side × side

= root 8 × root 8

= 8 square units.....