Find the area of the square inscribed in a circle of radius 10 cm
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Let ABCD be the square th
at is inscribed inside a circle having the centre at O.Now,
radius of the circle, r = 10 units
So, diameter of the circle, AC = 2r = 20 units
Now,
length of diagonal of square ABCD,
AC = 20 unitsWe know that each angle of a square is a right angle,
so ∠A = ∠B = ∠C = ∠D = 90°.
Also each side of the square is also equal.
So, AB = BC = CD = AD.In ∆ABC,
we haveAC2 = AB2 + BC2 [Pythagoras theorem]⇒(20)2 = AB2+AB2⇒2AB2 = 400⇒AB2 = 200Now, area of square ABCD = (side)2 = AB2 = 200 square units
at is inscribed inside a circle having the centre at O.Now,
radius of the circle, r = 10 units
So, diameter of the circle, AC = 2r = 20 units
Now,
length of diagonal of square ABCD,
AC = 20 unitsWe know that each angle of a square is a right angle,
so ∠A = ∠B = ∠C = ∠D = 90°.
Also each side of the square is also equal.
So, AB = BC = CD = AD.In ∆ABC,
we haveAC2 = AB2 + BC2 [Pythagoras theorem]⇒(20)2 = AB2+AB2⇒2AB2 = 400⇒AB2 = 200Now, area of square ABCD = (side)2 = AB2 = 200 square units
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Step-by-step explanation:
Square is inscribed in a circle.
So, the diagonal of square is the diameter of circle
Radius of circle = 10 cm
Diameter = 20 cm
Diagonal of square = 20 cm
We know that: Diagonal of a square = side*√2
20 = side *√2
side = 20/√2 = 10*2/√2 = 10*√2*√2/√2 = 10√2 cm
Area = side² = [10√2]² = 100*2 = 200 cm²
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