Question

Find the area of the square whose side is equal to the diagonal of a rectangle of length 3 cm and breadth 4 cm.

Answer 1

Answer:

Step-by-step explanation:

Ans is

5 cm

Answer 2

$\huge{\underline{\underline{\bf{Solution}}}}$

$\rule{200}{2}$

$\tt Given\begin{cases} \sf{Length \: of \: rectangle = 3 \: cm} \\ \sf{Breadth \: of \: rectangle = 4 \: cm} \end{cases}$

$\rule{200}{2}$

$\Large{\underline{\underline{\bf{To \: Find :}}}}$

We have to find the area of square.

$\rule{200}{2}$

$\Large{\underline{\underline{\bf{Explanation :}}}}$

It is given that, Diagonal of rectangle = Area of square.

So, We can find Diagonal of rectangle by Pythagoras theorem.

$\Large{\star{\boxed{\sf{H^2 = B^2 + P^2}}}}$

Where,

H = Diagonal

B = Breadth

P = Length

$\rule{150}{2}$

$\sf{→H^2 = 3^2 + 4^2} \\ \\ \sf{→H^2 = 16 + 9} \\ \\ \sf{→H^2 = 25} \\ \\ \sf{→H= \sqrt{25}} \\ \\ \sf{→H = (\sqrt{5})^2} \\ \\ \sf{→H = \pm 5}$

As, Diagonal or area of square can't be negative.

So, Area of square = 5 cm².