find the area of the triangle formed by the point (1,-1),(-4,6) and (-3,-5)
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Answer:
24 square units
Step-by-step explanation:
area of ∆ = (1/2) |x1(y2-y3) + x2(y3-y1) + x3(y1-y2)|
= (1/2) |1*(6-(-5)) + (-4)*(-5-(-1)) + (-3)*(-1-6)|
= (1/2) |1*11 + (-4)*(-4) + (-3)*(-7)|
= (1/2) |11+16+21|
= (1/2)*48
= 24 square units
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