Question

find the area of the triangle whose sides are 15cm,12cm and 17cm​

Answer 1

Answer:

find the area of the triangle whose sides are 15cm,12cm and 17cm

Answer 2

Step-by-step explanation:

Answer:

the \: side \: of \: triangle \: are \: 12cm \: 15cm \: 17cm \:thesideoftriangleare12cm15cm17cm

by \: herions \: formulabyherionsformula

s = \frac{a + b + c}{2}s=

2

a+b+c

s = \frac{12 + 15 + 17}{2}s=

2

12+15+17

s = \frac{44}{2}s=

2

44

s = 22cms=22cm

area = \sqrt{s(s - a)(s - b)(s - c)}area=

s(s−a)(s−b)(s−c)

area = \sqrt{22(22 - 12)(22 - 15)(22 - 17)}area=

22(22−12)(22−15)(22−17)

area = \sqrt{22 \times 10 \times 7 \times 5}area=

22×10×7×5

area = 10 \sqrt{77} {cm}^{2}area=10

77

cm

2