Question

find the area of the triangle with vertices (0,4) (0,-4) (6,0)

Answer 1

here is your answer
$1 \div 2(x1(y2 - y3)x2(y3 - y1)x3(x1 - x2) \\ 1 \div 2(0( - 4 - 0) + 0(0 - 4) + 6(4 + 4) \\ 1 \div 2(6(8)) \\ 1 \div 2 \times 48 \\ \\ 24$