find the area of the triangular whose sides 5cm,12cm,13cm resp. if the height of an equi.∆ meters 9cm than find its area?
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Answer:
Step-by-step explanation:
Here Sides are - 5 cm, 12 cm and 13 cm.
So, s = (a+b+c+)/2 where a,b, and c are sides of triangle
s = (5+12+13)/2 = 30/2 = 15
Area =√ 15( 15-5)(15-12)(15-13)
So, Area = 30
the smallest height will be on the largest base. So here the largest side is 13 cm.
So by area formula we have
Area = 1/2 ×base ×height
But area = 30
so, 30 = 1/2 × 13 ×height
height = 60/13 = 4.615 cm
hope so correct !!!!!!!!!!!!!!!!!
niralaritika:
plz mark is brainiest
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