Math, asked by AmandeepsinghSaini, 8 months ago

find the area of traingle whose vertices are (-8,-2),(-4,-6),(-1,5)​

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Answered by Sudhir1188
4

Step-by-step explanation:

\large{\boxed{\sf{\red{hope \: this \: will \: help \: you}}}} =

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Answered by Anonymous
12

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{ \huge \bf{ \mid{ \overline{ \underline{ \pink{QUESTION}}}}  \mid}} </p><p>

find the area of traingle whose vertices are (-8,-2),(-4,-6),(-1,5).

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{ \huge \bf{ \mid{ \overline{ \underline{ \blue{AñSweR♡}}}}  \mid}} </p><p>

LET => A = (-8,-2), B = (-4,-6), C = (-1,5)

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⠀⠀⠀⠀⠀⠀ \bf  \bold{ \red{ \underbrace{ \blue{ \underline { \underline{\: area \: of \: triangle \triangle</strong><strong>=</strong><strong>}}}}}}

</strong><strong>\</strong><strong>s</strong><strong>m</strong><strong>a</strong><strong>l</strong><strong>l</strong><strong>{ \pink{ \boxed{ \fbox{ \bf{ \bold { </strong><strong>\frac{1}{2}[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)] }}}}}}

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\large\underline{ \underline{ \green{ \bold{solution}}}}  =  &gt; ⠀⠀⠀⠀⠀⠀⠀

⠀⠀</strong><strong>\</strong><strong>\</strong><strong>=</strong><strong>&gt;</strong><strong>\frac{1}{2} [ - 8( - 6 - 5) +  - 4(5 + 2)  - 1( - 2 + 6)] \\  </strong><strong> </strong><strong>\</strong><strong>\</strong><strong> =  &gt;  \frac{1}{2}[88 - 28 - 4] </strong><strong>\</strong><strong>\</strong><strong>\\  =  &gt;  \frac{1}{2} [88 - 32] \\   \\ =  &gt;  \sf{ \cancel{ \dfrac{56}{2}}}28

⠀⠀⠀{ \boxed{ \fbox{ \purple{ \bf{area \: of \: triangle = 28sq \: unit}}}}}

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