Question

find the area of trapezium whose parallel sides are 33cm and 12cm and whose non parallel sides are of lengths 17cm and 10cm



Solve and send me an image.. Plz​

Answer 1

Answer:

y + z + 10 = 25

y² + x² = 13²

z² + x² = 14²

Isolate y in the first equation: y = 15 - z

Replace y² in the second equation with (15 - z)

(15 - z)² + x² = 13²

Isolate x² in the 3rd equation: x² = 14² - z²

Replace x² in : (15 - z)² + x² = 13² : with 14² - z²

(15 - z)² + 14² - z² = 13² n: Multiply out (15 - z)²

225 - 30z - z² + 196 - z² = 169 : Simplify by combining z² and -z² as zero

225 - 30z + 196 = 169 : Simplify by combining 225 and 196 as 421

421 - 30z = 169 : isolate z by adding 30 z to both sides

421 = 30z + 169 : isolate z by subtracting 169 from both sides

252 = 30z : isolate z by dividing both sides by 30

z = 8.4

Now solve for x, the height, because you know z

x² = 14² - z²

x² = 196 - 8.4²

x² = 196 - 70.56

x² = 125.44 : Take the square root of both sides

x = 11.2

According to the diagram 11.2 seems very reasonable

Area of a trapezium = [(b₁ + b₂)•h]/2

Area = [(25 + 10)•11.2]/2 = 196 cm²

Area = 196 cm²

Answer 2

Answer:

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