Find the area of trapezium whose parallel sides are of length 16cm and 22cm and whose diagonal is 12 cm
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Answer:
2.28 m2
Step-by-step explanation:
Given: Base of trapezium (b1)=16 dm
Base of trapezium (b2)=22 dm
Height of trapezium (h)=12 dm
Now, Area of trapezium =21×(b1+b2)×h
=21×(16+22)×12
=21×38×12
=228 dm2
=100228 m2[∵1 dm2=1001 m2]
=2.28 m2
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