Question

The base of triangle is 4m and height is 3m find its area

Answer 1

Given :-

• Base and height

To find :-

• Area

Formula used :-

$\boxed{{ \mathfrak{Area = \dfrac{1}{2} \times b \times h}}}$

Required answer :-

$\sf \implies \dfrac{1}{2} \times 4 \times 3 \\ \\ \sf \implies\dfrac{1}{2} \times12\\ \\ \sf \implies6 \\ \\ \therefore \blue{ \bf{ Area \: of \: triangle = 6m }}$

Figure :-

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1, 0)(1,0)(3,3)\qbezier(5,0)(5,0)(3,3)\qbezier(5,0)(1,0)(1,0)\put(2.85,3.2){ \bf A }\put(0.5,-0.3){ \bf C }\put(5.2,-0.3){ \bf B }\end{picture}$

Answer 2

${ \large{\sf{\pmb{Given}}}}$

• Base = 4m
• Height = 3m

${ \large{\sf{\pmb{To\: Find }}}}$

• Area

${ \large{\sf{\pmb{Formula\: Used }}}}$

• $\sf \pmb{ \dfrac{1}{2} \times b \times h}$

${ \large{\sf{\pmb{Solution}}}}$

$: \longrightarrow \: {\sf{ \dfrac{1}{2} \times 4 \times 3}}$

$: \longrightarrow \: {\sf{ \dfrac{1}{2} \times 12}}$

$: \longrightarrow \: {\underline{\sf{\blue{6}}}}$

$\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {minipage}{9cm}\\ \dag\quad \small\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}\end{gathered}\end{gathered}\end{gathered}$