Find the area of triangle formed by points (2,3) , (-1,0) , (2,-4)
pl. give answer as soon as possible
Answers
Answered by
1
Answer:
10.5 Sq. units
Step-by-step explanation:
Let the vertices of the triangle be A(2,3)=(x1,y1), B(-1,0) = (x2.y2) and C(2,-4)= (x3,y3)
Now area of the AABC
(1/2){x1(y2-y3) + x2(y3-y1) + x3(y1-y2)}
=(1/2)[2{0-(-4)} + (-1){-4–3}+2{3-0}]
=(1/2)(2x4+(-1)+(-7)+2x3}
=(1/2)(8+7+6)= (1/2)×21=21/2 = 10.5 sq.units.
Answered by
10
Answer:
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Step-by-step explanation:
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