Find the area of triangle , two side of which are 8 cm and 12 cm and the perimeter is 38 cm.
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Answer:
2×58
=116
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Area=√s(s﹣a)(s﹣b)(s﹣c)
P=a+b+c
s=a+b+c/2
Solving forA
A= 1/4√﹣P4+4P3a+4P3b﹣4(Pa)2﹣12P2ab 4(Pb)2+8Pa2b+8Pab2
= 1/4·√﹣384+4·383·8+4·383·12﹣4·(38·8)2﹣12·382·8·12﹣4·(38·12)2+8·38·82·12+8·38·8·122
ans≈38.24918cm²
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