Question

find the area of triangle,two sides which are 8cm,11cm and the perimeters is 32 cm​

Answer 1

Answer:

8cm of left side and 11cm is right side and 32cm its if length of total of 8cm and 11cm

hope you understand brai

Answer 2

Given :

Sides of Triangle are = 8 cm and 11 cm

Perimeter = 32 cm

To Find :

Area of Triangle .

Solution :

s = a + b + c/2

s = 8 + 11 + 13/2

s = 32/2

s = 16 cm

Now :

• Side a = 8 cm

• Side b = 11 cm

• Side c = 13 cm

Area = √s(s-a) (s-b) (s-c)

= √26(16-8) (16-11) (16-13)

= √16 × 8 × 5 × 3

= 2 × 2 × 2 × √ 2 × 5 × 3

$\longmapsto\sf{8\sqrt{30}{cm}^{2}}$

So , The area of the triangle is 8√30 cm² .