Question

If 5 x10¹⁹ free electrons are crossing through a given cross section of a conductor per second, then the magnitude of current flowing through the conductor is _________________

Answer 1

Answer:

65*2³

Explanation:

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Answer 2

Answer:

The correct answer is 8A of current.

Explanation:

charge of electrons = 1.6×10^-19

no. of electrons = 5×10^19

current = charge of electrons× no. of free electrons

= 1.6×10^-19× 5×10^19

= 8A