Question

Find the area q a sector of
circle with radius
6cm if angle
the sector is 60°.ܩܗ​

Answer 1

Answer:

Radius= 6cm

theta= 60

Hence, area= theta/360* pi*r^2

= 1/6* 22/7*36

= 18.857 cm^2

Answer 2

Correct Question :-

Find the area of a sector of a circle with radius 6 cm if angle of the sector is 60°.

Given :-

• Radius of circle = 6 cm

• Angle of the sector (θ) = 60°

To find :-

• The area of a sector of a circle = ?

Solution :-

we know that,

$\green{\bigstar}\:\:{\underline{\boxed{\bf\red{Area\:of\:sector=\dfrac{\theta}{360}\times{\pi}{r}^{2}}}}}$

$\rm\longrightarrow\:Area\:of\:sector=\dfrac{\cancel{60\degree}}{\cancel{360}}\times\dfrac{22}{7}\times{(6)}^{2}$

$\rm\longrightarrow\:Area\:of\:sector=\dfrac{1}{\cancel{6}}\times\dfrac{22}{7}\times{\cancel{6}}\times{6}$

$\rm\longrightarrow\:Area\:of\:sector=\dfrac{22\times{6}}{7}$

$\rm\longrightarrow\:Area\:of\:sector=\dfrac{132}{7}\:{cm}^{2}$

Hence, the area of a sector of a circle will be 132/7 cm².

More information :-

Sector of a circle :-The region enclosed by an arc of a circle and it's two bounding radii is called a sector of the circle.

Radius :- A line segment joining the centre of a circle and a point on the circle is called a radius of the circle.

Formula :-

Circumference and area of a circle,

• circumference of the circle = 2πr
• Area of the circle = πr²
• Area of semicircle = ½ πr²
• Perimeter of semicircle = (πr + 2r)