Question

Find the average velocity of a projectile between the instants it crosses half the maximum height. It is projected with a speed u at an angle θ with the horizontal.Concept of Physics - 1 , HC VERMA , Chapter "Rest and Motion : Kinematics

Answer 1

Solution:
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Time of Flight=T= 2usinθ/g
Average velocity= Change in displacement /Time

From the figure we an see that AB is horizontal.
So there is no effect, of vertical component of the velocity during its displacement .
Because moves at a constant displacement of ucosθ in horizontal direction .
The average velocity during its displacement would be ucosθ in the horizontal direction.

Answer 2

HEY!!

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▶Initial velocity of the projectile = u

▶Angle of projection = θ

Average velocity of the projectile
Average velocity=
Change in displacement/Time

▶By the symmetry of figure, it can be said that the line joining points A and B is horizontal.

▶So, there will be no effect of the vertical component of velocity of the projectile during displacement AB.

▶We know that the projectile moves at a constant velocity ucosθ in horizontal direction.

▶▶Hence, the average velocity of the projectile is ucosθ.