∆ LMN ~ ∆PQR, 9 × A (∆PQR) = 16 × A (∆LMN). If QR =20 then find MN.
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Answered by
476
Heya !!!
Given that ∆LMN and ∆PQR similar triangles.
9 × Area ( ∆PQR) = 16 × Area(∆LMN)
Area of ∆LMN : Area of ∆PQR = 9:16
We know that,
Area of two similar triangles is always Equal to square of their corresponding sides.
Therefore,
Area ( ∆LMN) / Area ( ∆PQR) = (MN/QR)²
9/16 = (MN)² / (20)²
9/16 = (MN)² / 400
(MN)² = 9×400/16
(MN) = ✓9×400/16
MN = 3×20/4
MN = 3 × 5 = 15 cm
HOPE IT WILL HELP YOU....... :-)
Given that ∆LMN and ∆PQR similar triangles.
9 × Area ( ∆PQR) = 16 × Area(∆LMN)
Area of ∆LMN : Area of ∆PQR = 9:16
We know that,
Area of two similar triangles is always Equal to square of their corresponding sides.
Therefore,
Area ( ∆LMN) / Area ( ∆PQR) = (MN/QR)²
9/16 = (MN)² / (20)²
9/16 = (MN)² / 400
(MN)² = 9×400/16
(MN) = ✓9×400/16
MN = 3×20/4
MN = 3 × 5 = 15 cm
HOPE IT WILL HELP YOU....... :-)
faizan76:
Thanks
Answered by
113
Answer:
Step-by-step explanation:
Given that ∆LMN and ∆PQR similar triangles.
9 × Area ( ∆PQR) = 16 × Area(∆LMN)
Area of ∆LMN : Area of ∆PQR = 9:16
We know that,
Area of two similar triangles is always Equal to square of their corresponding sides.
Therefore,
Area ( ∆LMN) / Area ( ∆PQR) = (MN/QR)²
9/16 = (MN)² / (20)²
9/16 = (MN)² / 400
(MN)² = 9×400/16
(MN) = ✓9×400/16
MN = 3×20/4
MN = 3 × 5 = 15
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