Question

Find the base of a triangle whose area is 0.48dm2 and altitude is 8cm

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Answer 1

Step-by-step explanation:

Area of a triangle= 0.48dm sq.

Altitude= 8cm

Base= ?

So, we know area= 1/2* base* altitude

Let the base be 'x'

=1/2*x*8cm = 0.48dm sq.

(0.48* 1/10* 1/10 = 0.48*1/100= 0.0048cm)

=1/2*x*8= 0.0048

=4x = 0.0048

= x = 0.0048/4

= x = 0.0012

Therefore, base of the triangle is 0.0012cm