find the capacity of a rectangular cistern in litres whose dimensions are 11.2 m*6m*5.8m. find the area of iron sheet required to make the cistern
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Answered by
518
Cisterns are cuboidal in shape.
dimension = 11.2m × 6m × 5.8m
capacity = volume = lbh = 11.2m × 6m × 5.8m = 389.76 m³
1 m³ = 1000l
So capacity = 389.76×1000 = 389760 Litre
area of iron sheet required = total surface area of cistern
= 2(lb+bh+lh)
= 2(11.2×6 + 6×5.8 + 11.2×5.8)
= 2(166.96) m²
= 333.92 m²
capacity = 389.86 m³
area of sheet required = 333.92 m²
dimension = 11.2m × 6m × 5.8m
capacity = volume = lbh = 11.2m × 6m × 5.8m = 389.76 m³
1 m³ = 1000l
So capacity = 389.76×1000 = 389760 Litre
area of iron sheet required = total surface area of cistern
= 2(lb+bh+lh)
= 2(11.2×6 + 6×5.8 + 11.2×5.8)
= 2(166.96) m²
= 333.92 m²
capacity = 389.86 m³
area of sheet required = 333.92 m²
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24
Step-by-step explanation:
We know that volume of cuboid = length × breadth × height Volume of the cistern = 11.2 × 6 × 5.8 = 389.76 m3 = 389.76 × 1000 = 389760 liters. Area of the sheet that required to make the cistern = total surface area of the cistern we know that total surface area of cuboid= 2(l b + b h + h l) = 2 (11.22 × 6 + 6 × 5.8 + 5.8 × 11.2) = 2 (67.2 + 64.96 + 34.8) = 333.92 cm
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