Find the centerand radiusof circle [x-1/2]^2+[y+1/3]^2=1/36
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Answer:
The standard form of the
equation of a circle
is.
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣
∣
2
2
(
x
−
a
)
2
+
(
y
−
b
)
2
=
r
2
2
2
∣
∣
∣
−−−−−−−−−−−−−−−−−−−−−−−−−−
where (a ,b) are the coordinates of the centre and r, the radius.
⇒
(
x
−
3
)
2
+
(
y
−
0
)
2
=
2
2
is in this form
⇒
centre
=
(
3
,
0
)
and radius
=
2
Step-by-step explanation:
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