Find the centroid of (log2
1, tan45°), (cos90°, log cot45°) and (5, 7).
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Given : three points cordinates (log₂1 , tan45° ) ( Cos90° , log Cot45° ) and ( 5 . 7)
To find : Centroid
Solution:
(log₂1 , tan45° ) ( Cos90° , log Cot45° ) and ( 5 . 7)
first Simplify the points
log₂1 = 0
tan45° = 1
Cos90° = 0
log Cot45° = log 1 = 0
Hence points are
( 0 , 1) ( 0 , 0) and ( 5 , 7)
Centroid = ( 0 + 0 + 5)/3 , ( 1 + 0 + 7)/3
= 5/3 , 8/3
Centroid = ( 5/3 , 8/3)
Learn more:
find the centroid of the triangle xyz whose vertices are x 3, -5, y -3, 4 ...
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