find the centroid of the triangle ABC whose vertices are A(-3,0) B(5,-2)and C(-8,5)
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Answered by
26
coordinate of centroid=[(-3+5+-8)/3 , (0+-2+5)/3],
=[(-6)/3 , (3)/3],
=[-2 , 1]
=[(-6)/3 , (3)/3],
=[-2 , 1]
Answered by
13
centroid of triangle=(x1+X2+x3)/3
=-3+5+(-8)/3=-6/3=2
(Y1+y2+y3)/3
=0+(-2)+5/3
=1
so,(x,y)=(2,1)
=-3+5+(-8)/3=-6/3=2
(Y1+y2+y3)/3
=0+(-2)+5/3
=1
so,(x,y)=(2,1)
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