find the centroid of the triangle whose vertices are 3,-7 -8,8 and 5,10
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Answered by
5
3+(-8)+5/3 and (-7)+5+10/3 that is 0,8/3
Takshika:
That's wrong
Answered by
8
Formula to find the centroid of a triangle is (x1+x2+x3/3) , (y1+y2+y3/3). You'll the answer if you apply this formula.. :-)
hope it helps..
Thumps up plz..
hope it helps..
Thumps up plz..
Let A , B and C are three vertices of
the triangle
( x1 , y1 ) = A ( 3 , - 7 )
( x2 , y2 ) = B ( - 8 , 6 )
( x3 , y3 ) = C ( 5 , 10 )
Centroid ( G )
= ( x1+x2+x3/3 , y1+y2+y3/3 )
= ( 3-8+5/3 , -7+6+10/3 )
= ( 0 , 9/3 )
= ( 0 , 3 )
G = ( 0 , 3 )
the triangle
( x1 , y1 ) = A ( 3 , - 7 )
( x2 , y2 ) = B ( - 8 , 6 )
( x3 , y3 ) = C ( 5 , 10 )
Centroid ( G )
= ( x1+x2+x3/3 , y1+y2+y3/3 )
= ( 3-8+5/3 , -7+6+10/3 )
= ( 0 , 9/3 )
= ( 0 , 3 )
G = ( 0 , 3 )
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