Question

find the centroid of the triangle xyz whose vertices are x(3,-5) , y(-3,4) and z(9,-2) using section formula and midpoint formula.

Answer 1

Here, (x1 = 3, y1 = -5), (x2 = -3, y2 = 4) and (x3 = 9, y3 = -2),

Let G (x, y) be the centroid of the triangle ABC. Then,

x = (x1+x2+x3)/3 = (3+(-3)+9)/3 = 3

y = (y1+y2+y3)/3 = ((-5)+4+(-2))/3 = -1

Therefore, the coordinates of the centroid G of the triangle ABC are (3, -1)

Thus, the coordinates of the point of intersection of the medians of triangle are (3, -1).