Question

Subtract 12a² - 9ab + 10b² from 4a² - 5ab - 21b² by horizontal method.
pls answer the question ​

Answer 1

Answer:

hi guys

Step-by-step explanation:

GIVEN:12a²-9ab+10b² take as 1

4a²-5ab-21b² take as 2

we have to divide 1-2

(12a²-9ab+10b²)-(4a²-5ab-21b²)

TAKE ELEMENTS COMMON

12a²+4a²-9ab+5ab+10b²+21b²

16a²-4ab+31b²

I hope you understand it

Answer 2

$\color{red}{QUESTION}$

Subtract 12a² - 9ab + 10b² from 4a² - 5ab - 21b² by horizontal method.

$\color{blue}{ANSWER}$

12a² - 9ab +10b² - (4a² - 5ab -21b² )

=> 12a² - 9ab +10 b² - 4a² +5ab +21b² [ sign Changed because the miuns sign is outside the equation (4a² -5ab -21b²) ]

To solve this we will bring the like teams together first, we get,

=> 12a² -4a² -9ab +5ab +10b² +21b²

=> 8a² -4ab + 31b²

Hence, 8a² -4ab + 31b² is your answer