Question

find the coefficient of x² and x in the product of (x-5)(x+3)(x+7)​

Answer 1

Explanation:

$(x - 5)(x + 3)(x + 7) \\ \\ = ( {x}^{2} + 3x - 5x - 15)(x + 7) \\ \\ = ( {x}^{2} - 2x - 15)(x + 7) \\ \\ = {x}^{3} + 7 {x}^{2} - 2 {x}^{2} - 14x - 15x - 105 \\ \\ = {x}^{3} + 5 {x}^{2} - 29x - 105 = 0$

Coefficient of x^2 = 5

Coefficient of x = -29

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Answer 2

Answer:

$(x - 5)(x - 3)(x - 7)$

$solution \: =$

= {(x-5)(x-3)}(x-7)

={x(x-3)-5(x-3)}(x-7)

={x²-3x-5x+15}(x-7)

=(x-7){x²-3x-5x+15}

=(x-7){x(x-3)-5(x-15)}

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