Find the common difference of an ap whose first term is 5 and the sum of the its four te\rms is half the sum if the next four terms
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a=2
S4=1/2 (S8-S4)
40+12d=20+22d
20=22d-12d
20=10d
d=2
S4=1/2 (S8-S4)
40+12d=20+22d
20=22d-12d
20=10d
d=2
Answered by
1
Hope it helps you!
Regards,
Shobana
^_^
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