Math, asked by shreeeeeeeya5171, 1 year ago

Find the point on the x axis which is equidistant from the points (-2 5) and (-2 9) by distance formula

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Answered by khiljee

1

As can be seen from the picture,
BX is always greater than AX for any point X on X-axis.. Therefore, no such points exist where AX = BX

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