Math, asked by arthakur, 8 months ago

find the compound interest and the amount on rupees 5000 the annual interest rate of 8% for 2 years 6 month​

Answers

Answered by nehaparveen75
3

Step-by-step explanation:

P = Rs 5,000

t = 1 year 6 months, so t = 3

r = 8% per annum

C.I=P(1+

100

r

)

t

−P

=P((1+

100

r

)

t

−1)

=5000((1+

100

8

)

3

−1)

=5000(0.2597)

=Rs1298.5(Rs1298.5)

Answered by manjubala39
4

HELLO!!

ANSWER:

Amount = ₹5616

Compound interest = ₹616

EXPLANATION:

GIVEN:

Principal (P) = ₹5000

Rate of interest (r) = 8% p.a

Time (n) = 2 years 6 months = 18 months = 18/12 years = 3/2 years = 1½ years

TO FIND:

Amount and Compound interest

SOLUTION:

Amount (A) = P (1 + r/100)¹ [1 + ½ (r/100)]

A = 5000(1 + 8/100) [1 + ½ (8/100) ]

A = 5000(1 + 0.08) [1 + 8/200 ]

A = 5000(1.08) [1 + 0.04 ]

A = 5000(1.08) [1.04]

A = 5000(1.1232)

Amount = ₹5616

Compound interest (CI) = A - P

CI = 5616 - 5000

Compound interest = ₹616

HOPE IT HELPS YOU!!

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