find the compound interest on 2400 at 10% per annum for 2years 4 months
Answers
Answered by
0
A= P(1+r/100)^t
=2400(1+10/100)^2×(1+10/100)^1/3
=2400(110/100)^2×(1+10/300)
=2400(11/10)^2×(31/30)
=2400×11/10×11/10×31/30
=2400×11×11×31/10×10×30
= 9002400/3000
= 3000.80
CI=A-P
=600.80
Similar questions