Math, asked by gurucharan5, 1 year ago

sin23°cos22°+cos25°sin22°=1/√2

Answers

Answered by niskarsh1218
3
SinACosB+CosASinB = Sin(A+B)
so,
sin(23°+22°)
=sin45°
which is 1/√2
hence LHS = RHS

gurucharan5: Answer
niskarsh1218: firstly u see know that a²-b² =( a+b) (a-b)
niskarsh1218: apply this then sin square 75° - cos square 45° becomes
niskarsh1218: (sin75+cos45) (sin75-cos45)
niskarsh1218: then u break sin75 into sin (45 + 30)
gurucharan5: Ohh
gurucharan5: Thnx bro
niskarsh1218: and then apply sin(a+b) =sinacosb+cosasinb formula
gurucharan5: I understood
niskarsh1218: ok
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