Question

Find the compound interest on 4000 for 5 years at 10% p.a.

Give full explanation!
​

Answer 1

$\huge \sf {\orange{\underline{\purple{\underline{Question :-}}}}}$

Find the compound interest on 4000 for 5 years at 10% p.a.

$\huge \sf {\orange {\underline {\pink{\underline{Answer :-}}}}}$

→Principal (P) = Rs.4000

Since the interest is compounded yearly the number of conversion periods in 5 years are 5.

Also the rate of interest per conversion period (12 months) is 10% × 5 = 50% (0.5 in decimal) .

Thus the amount $\sf{A_n}$ (in Rs.) is given by

$\checkmark~\sf\purple{A_n~=~P~(1~+~i)^n~}$

$\longmapsto~\rm{A_n~=~4000~(1~+~0.5)^3~}$

$\longmapsto~\rm{A_n~=~4000\times{3.375}~}$

$\longmapsto~\rm{A_n~=~Rs.13500~}$

★The compound interest is therefore,

→ Rs. (13500 - 4000)

→ Rs.9500

${\huge{\underline{\small{\mathbb{\pink{HOPE\:HELPS\:UH :)}}}}}}$

Answer 2

Answer pls mark me as brainliest and pls pls follow me pls bro or sis

1082

step by step explanation

principal(P) =Rs 4000

Rate of Interest(r)= 10%

timr=2.5yearsHere first we take n=3 years.

A=P(1+r/100)n Where A = Amount and n = number of years

A=4000(11/10)2

A=4000(121/100)

A=Rs 4840

The Amount after twoyears = Rs 4840

Now Principal=Rs 4840

Simple interest for last 1/2 year is = PRT/100=(4840*10*1/2)/100= Ts 242

Amount after 21/2 year = Rs 4840 + Rs 242 = Rs 5082

C.I=A-P

C.I =Rs 5082 -Rz4000=Rs1082

therefore the compound interest is rs 1082.