find the compound interest on rupees 10000for 1yrs at 10% pa if the interest is compounded quaterly
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Answer:
11038.12
Explanation:
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Answered by
0
Answer:
₹1038.13
Explanation:
Let the principal be ₹P.
CI=P{(1+r )⁴ⁿ -1}
¹⁰⁰ˣ⁴
=₹10000{(1+₄₀₀¹⁰)⁴-1}
=₹10000{(⁴¹⁰₄₀₀)(⁴¹⁰₄₀₀)(⁴¹⁰₄₀₀)(⁴¹⁰₄₀₀)-1}
=₹10000 x 410 x 410 x 410 x 410
⁴⁰⁰ ˣ ⁴⁰⁰ ˣ ⁴⁰⁰ˣ ⁴⁰⁰
=₹11038.12890625
CI ≈₹11038.13
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