Question

find the compound interest on rupees 64000 at a rate of 12 pcpa for 3 years.​

Answer 1

Step-by-step explanation:

P- 64000

n- 3 years (36 months )

R- 12%

Formula:

*Note: You can use one of the three formulas

$1. \: i = \frac{p \times t \times r}{100}$

$2. \: i = \frac{p \times n(n + 1)}{2 \times 12} \times \frac{r}{100}$

Substitute the symbols with the values and the simplify to get the answer..

I = 64000×36(36+1) × 12

2×12 100

0's will get cancelled, 36 will be simplified by 12 and become 3 , 12 will be simplified by 2 and become 6....the equation will be as follows....

I = 640×3(36+1) × 6

= 4,03,200

Feel free correct me if I am wrong

Pls mark brainliest if the answer correct.