Math, asked by sagarzanjad, 1 year ago

find the consecutive term of AP whose sum is -3 and product of their cube is 512?


RaunakRaj: it is the or three
sagarzanjad: it 3 sorry typing mistake
RaunakRaj: and u r sure that it is product. It might be sum.
RaunakRaj: or there will not be cude
RaunakRaj: cube*
sagarzanjad: it's all right rather than 3

Answers

Answered by praharajsabhrat
3
There are 2 possible series
Plz brainliest
Attachments:

RaunakRaj: 3, -1 and -5 is not possible as the product of cube is not 512.
Answered by RaunakRaj
7
Let the three term be (a-d), a, (a+d)
So,
a-d+a+a+d= -3
3a= -3
a=(-1)

(a-d)^3×a^3×(a+d)^3=512
((a-d)(a+d))^3×a^3=512
((a^2-d^2)a)^3=512
((1-d^2)(-1))=8
1-d^2=(-8)
d^2=9
d=+3 or -3
So,
three terms are (-4), (-1) and 2.
PLZ MARK IT AS BRAINLIEST.
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