Question

FIND THE CONTINUED PRODUCT
i) (a+1)(a-1)(a square +1)
answer the question ​

Answer 1

Answer:

a^8+1

Step-by-step explanation:

(a+1)(a-1)(a^2+1)

= (a^2+1^2)(a^2+1) [(a+b)(a-b) = a^2+b^2]

= (a^2+1)(a^2+1)

= (a^2+1)^2

= a^2(a^2+1) + 1(a^2+1)

= a^4+a^2+a^2+1

= a^8+1 (Ans.)