Question

find the coordinate of a point on y axis which is equidistant from the points (13,2) and (12,-3) ​

Answer 1

Answer:

y=2

Step-by-step explanation:

Let P(0, y) be the required point and the given points be A(12 , -3) and B (13 , 2) Then PA = PB (given)

√(12−0) ²+(−3−y)²

=√(13−0) ²

+(2−y)²

⇒ √144+(y+3)²= √

169+(2−y)²  

⇒y=2

∴ The required point on Y-axis is (0, 2).