Question

Find the corresponding angle when a diver at a depth of 12m in water
(3) sees the sky in a cone of semi-vertical angle​

Answer 1

Given : μ=

3

4

and μ

air

=1

The ray emerges out of water making an angle 90

o

with the water surface, i.e r=90

o

Using Snell's law of refraction at point A:

⇒μsinθ=μ

air

sinr

⇒

3

4

×sinθ=1×sin90

o

⇒

3

4

×sinθ=1×1

⇒ sinθ=

4

3

⇒ θ=sin

−1

(

4

3

)