Question

Find the cost of flooring a room 6.5m and 5m with sq tiles of side 25cm at the rate of Rs. 1880 per hundred tiles

Answer 1

area of floor=650*500
=3,25,000 cm^2

area of each tile=25*25
=625cm^2

tiles required= 325000/625
=520 tiles

cost of each tile= 1880/100
=Rs.18.80

cost of 520=Rs.9776

Answer 2

heya frnd!

here's ur answer....

$given \: the \: lengt \: of \: the \: floor \: is \: 6.5m \\ and \: breadth \: of \: the \: floor \: is \: 5m \\ \\ area \: of \: the \: floor = length \times breadth \\ = 6.5 \times 5 \\ = 32.5m ^{2} \\ \\ given \: length \: of \: the \: square \: tile \: is \\ 25cm \\ \\ hence \: area \: ofthe \: tile = side \times side \\ = 25 \times 25 \\ = 625cm ^{2} \\ \\ in \: metres = \frac{625}{100} \\ = 6.25m ^{2} \\ \\ total \: number \: of \: tiles \: required \: to \\ cover \: the \: floor = \frac{32.5}{6.25} \\ = 5.2 \: tiles \: required \\ \\ if \: 100 \: tiles \: cost \: 1880rs \: then \: 1 \: tile \\ will \: cost = \frac{1880}{100} \\ = 18.8 \:rs \\ \\ therefore \: total \: cost \: of \: covering \: the \: \\ floor \: with \: tiles = 5.2 \times 18.8 \\ = 97.76 \: rs \\ \\ hope \: this \: helps \: u......$

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