Question

Find the cubic polynomial with the sum of its zeros, sum of the products of its zeros taken two at a time and product of its zeros as 0,−7 and −11 respectively​

Answer 1

Answer:

k[x^3+(-7x)-(-11)]

sum of its zeros : 0

product of its zeros taken two at a time : -7

product of its zeros : -11

to form a cubic polynomial :

k[x^3-(sum of its zeros x^2)+(product of zeros taken two at a time x)+(product of zeros)]

k[x^3-(0x^2)+(-7x)-(-11)]

k[x^3-7x+11]

Answer 2

Answer:

x³-7x+11

Step-by-step explanation:

skeletal cubic polynomial=ax³-bx²+cx-d

here, a=1,b= sum of zeroes, c= sum of the products of its zeros taken two at a time and d= product of its zeroes.

x³-7x+11