Find the current drawn from the battery by network of four resistors shown in the figure?
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Answer:
Current is 0.3 Ampere
Explanation:
R1= 10 + 10 = 20 Ohm
R2= 10 + 10 = 20 Ohm
1/Rp = 1/R1 + 1/R2
1/Rp = 1/20 + 1/20
1/Rp = 2/20
1/Rp = 1/10
Rp = 10 Ohm
V= IR
I = V/R
I = 3/10
I = 0.3 Ampere
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