Question

Find the curved surface area of the frustum of a cone, the diameters of whose circular ends are 20 m and 6 m and its height is 24 cm.
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Answer 1

Answer:

1021.247

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given Find the curved surface area of the frustum of a cone, the diameters of whose circular ends are 20 m and 6 m and its height is 24 cm.

• Now in  a frustum of a cone we need to find the slant height.
• Now diameters of circular ends of the frustum of a cone are 20 m and 6 m
• So the radius will be 20/2 = 10 m and 6/2 = 3 m
• So R = 10 and r = 7 , but r = 10 – 3 = 7
• Now slant height = √h^2 + l^2
•                         = √24^2 + 7^2
•                          = √576 + 49
•                           = √625
•                           = 25
• So curved surface area CSA = π(R + r)l
•                                              = 22/7 x (10 + 3) 25
•                                              = 7150 / 7
•                 = 1021.4 sq cm

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https://brainly.in/question/7066575