Question

The free energy change for the following reaction are given below:
C2h2+5/2o2 gives 2co2+h2o delta G=-1234kj
C+o2 gives co2 delta G=-394kj
H2+1/2o2 gives H2o delta G=-237 kh

Answer 1

Answer:

H² +o²

-1234kj

C+o2 gives co2 delta G=-394kj

H2+1/2o2 gives H2o delta G=-237 kh

Answer 2

The standard free energy change for the reaction H₂ (g) + 2C (s) → C₂H₂ (g) is 209 KJ

Given:

C₂H₂ (g) + 5/2O₂ (g) → 2CO₂ (g) + H₂O (l); ΔG˚ = -1234 kJ

C (s) + O₂ (g) → CO₂ (g); ΔG˚ = -394 kJ

H₂ (g) + ½O₂ (g) → H₂O (l); ΔG˚ = -237 kJ

Explanation:

Now, the reaction to which we need to fine free energy change is:

H₂ (g) + 2C (s) → C₂H₂ (g)

ΔG for the given reaction is given as:

ΔG = -ΔG₁ + 2ΔG₂ - ΔG₃

ΔG = - (-1234) + 2(-394) - (-237)

On calculating the number in right hand side, we get the free energy change,

∴ ΔG = 209 KJ