Question

find the daigonal of the cube whose each edge is 4 cm

Answer 1

diagonal of cube is a/√3=4/√3

Answer 2

Side of cube, a = 4cm
Alternate sides of a cube are at 90%, so the diagonal becomes hypotenuse and the sides become perpendicular and base.
Then, by pythagoras theorem
H^2 = P^2 + B^2
H^2 = (4*4)+(4*4)
H^2 = 16 + 16
H=
$\sqrt{32}$
H= 5.65685cm
Diagonal of cube = 5.6cm app.