Question

Find the degree measure corresponding to 11/6 radian

Answer 1

Step-by-step explanation:

Concept :- use the reaction here , D/180° = C/π

Where D = angle in degree

C = angle in radian.

(i)C = 11/16

D= ?

D/180° = (11/16)/π

D = 180×11/16π°

= (180×11×7/16×22)°

= (315/7)°

= 39° + (3/8)°

= 39° + {(3/8)×60}' [ 1°=60']

= 39°+ (45/2)'

=39° + 22' + (1/2)'

= 39°22' + (60/2)" [ 1' = 60"]

= 39°22'30"

Answer 2

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cosA=5/13

sinA=-√(1-cos^2A) (since theta is in 4th quadrant)

i.e. sinA=-√144/169

=-12/13

tanB=-15/8

sinB=+(15)/√{(-15)^2+(8)^2} (B is in Q2)

i.e. sinB=15/17

cosB=tanB/sinB

i.e. cosB=-15/8 * 17/15

cosB=17/8

now

sin(A+B)=sinAcosB+cosAsinB

sin(A+B)=(-12/13)(17/8)+(5/13)(15/17)

={1/13}(-51/2 + 75/17)

=(1/13)(-710/34)

=-710/442

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