find the derivative of logSin4x.
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Answer:
Step-by-step explanation:
sin
(
4
x
)
d
d
x
[
sin
(
4
x
)
]
Convert from
1
sin
(
4
x
)
to
csc
(
4
x
)
.
csc
(
4
x
)
d
d
x
[
sin
(
4
x
)
]
Differentiate using the chain rule, which states that
d
d
x
[
f
(
g
(
x
)
)
]
is
f
'
(
g
(
x
)
)
g
'
(
x
)
where
f
(
x
)
=
sin
(
x
)
and
g
(
x
)
=
4
x
.
Tap for more steps...
csc
(
4
x
)
(
cos
(
4
x
)
d
d
x
[
4
x
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