Question

Find the devirative of y=2x^4+x^3-3x^2-2x+5

Answer 1

$\frac{dy}{dx} <strong>= 8·[tex]x^{3}$  + 3·$x^{2}$ - 6·x - 2

Step-by-step explanation:

Given, y =2·$x^{4}$ + $x^{3}$ - 3·$x^{2}$ - 2·x + 5

∴ $\frac{dy}{dx} = 2·4·[tex]x^{3}$  + 3·$x^{2}$ - 3·2x - 2 + 0

⇒$\frac{dy}{dx} <strong>= 8·[tex]x^{3}$  + 3·$x^{2}$ - 6·x - 2

Hence, $\frac{dy}{dx} <strong>= 8·[tex]x^{3}$  + 3·$x^{2}$ - 6·x - 2.