find the diameter of a circle whose area is 16 times the area of the circle with diameter 7 cm.
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Answered by
6
Heya !!
Diameter of another circle = 7 cm.
Area. = πr² = 22/7 × 7 × 7
=> ( 22 × 7 )
=> 154 cm².
According to the question,
Area of first circle = 16 ( Area of another circle )
πR² = 16 × 154
22/7 × R² = 2464
R² = 2464 × 7 /22
R² = 784
R = √784
R = 28 cm
Diameter ( D ) = 2 × R = 2 × 28 = 56 cm.
Diameter of another circle = 7 cm.
Area. = πr² = 22/7 × 7 × 7
=> ( 22 × 7 )
=> 154 cm².
According to the question,
Area of first circle = 16 ( Area of another circle )
πR² = 16 × 154
22/7 × R² = 2464
R² = 2464 × 7 /22
R² = 784
R = √784
R = 28 cm
Diameter ( D ) = 2 × R = 2 × 28 = 56 cm.
Anonymous:
hi
Answered by
4
area of small circle = π r²
= 22/7 x 3.5 x 3.5
= 11 x 3.5
area of large circle = 16 x 11 x 3.5
= 616 cm ²
radius² = 616 x 7/22
= 196
r = 14
d = 14x 2
= 28cm
= 22/7 x 3.5 x 3.5
= 11 x 3.5
area of large circle = 16 x 11 x 3.5
= 616 cm ²
radius² = 616 x 7/22
= 196
r = 14
d = 14x 2
= 28cm
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